Gosh this is off-topic, but I'm still unclear:

Couldn't there be a higher alkyl group (ethyl, propyl, etc.) attached to the alpha, N, or 3,4-dioxy positions? How does this system show that a methyl group, and only a methyl group, could be in those places?

Anyway, I've often wondered why Shulgin was inconsistent with his stereochemistry in PiHKAL's diagrams, as you mention.

Thanks for the lesson, and I don't think Shulgin or the Erowids would mind the diagram being linked to for non-commercial purposes.


*edit* OK, I missed this:

Quote:

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the appropriate number of hydrogens are assumed to be joined to any carbon such that all four bonding slots of the carbon are completed (unless otherwise illustrated)

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